27^x-1=(1/9)^x

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Solution for 27^x-1=(1/9)^x equation: 



27^x-1=(1/9)^x

We move all terms to the left:

27^x-1-((1/9)^x)=0



Domain of the equation: 9)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

27^x-((+1/9)^x)-1=0

We multiply all the terms by the denominator


27^x*9)^x)-((-1*9)^x)+1=0

We add all the numbers together, and all the variables

27^x*9)^x)-((-9)^x)+1=0

Wy multiply elements

243x^2-9)^x)+1=0

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